03-02-2010, 02:11 AM
I posted about this earlier in the year.
If you do the math and multiply Pi times the radius squared.
for a 8" it would be (4x4)xPi or 3.141. This equals 50.25 square inches of ice being drilled.
for a 5" it would be (2.5x2.5) x3.141. This equals 19.63 square inches of ice being drilled.
Less than 1/2 the ice is being drilled so it should take less than 1/2 the effort.
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If you do the math and multiply Pi times the radius squared.
for a 8" it would be (4x4)xPi or 3.141. This equals 50.25 square inches of ice being drilled.
for a 5" it would be (2.5x2.5) x3.141. This equals 19.63 square inches of ice being drilled.
Less than 1/2 the ice is being drilled so it should take less than 1/2 the effort.
[signature]